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[bug#51028,2/7] gnu: Add julia-pyplot.

Message ID ba7ca383dce4662eace34bb70defc2eb0d4d51e4.1633411929.git.efraim@flashner.co.il
State Accepted
Headers show
Series More julia packages | expand

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Commit Message

Efraim Flashner Oct. 5, 2021, 9:47 a.m. UTC 
* gnu/packages/julia-xyz.scm (julia-pyplot): New variable.
---
 gnu/packages/julia-xyz.scm | 29 +++++++++++++++++++++++++++++
 1 file changed, 29 insertions(+)

Comments

Simon Tournier Oct. 11, 2021, 11:22 a.m. UTC | #1 
Hi,

I would write:

> +    (description "This module provides a Julia interface to the Matplotlib

  (description "This package provides a Julia interface to the Matplotlib


LTGM.

Cheers,
simon
diff mbox series

Patch

diff --git a/gnu/packages/julia-xyz.scm b/gnu/packages/julia-xyz.scm
index 2238acf103..5925ca2417 100644
--- a/gnu/packages/julia-xyz.scm
+++ b/gnu/packages/julia-xyz.scm
@@ -3280,6 +3280,35 @@  (define-public julia-pycall
 share large data structures between Julia and Python without copying them.")
     (license license:expat)))
 
+(define-public julia-pyplot
+  (package
+    (name "julia-pyplot")
+    (version "2.10.0")
+    (source
+      (origin
+        (method git-fetch)
+        (uri (git-reference
+               (url "https://github.com/JuliaPy/PyPlot.jl")
+               (commit (string-append "v" version))))
+        (file-name (git-file-name name version))
+        (sha256
+         (base32 "007zs0imfgs69f30pp2a3rc93kl0qiq7qjx6ig35z4wzkmps4skd"))))
+    (build-system julia-build-system)
+    (propagated-inputs
+     `(("julia-colors" ,julia-colors)
+       ("julia-latexstrings" ,julia-latexstrings)
+       ("julia-pycall" ,julia-pycall)
+       ("julia-versionparsing" ,julia-versionparsing)
+       ;; python-matplotlib is expected to be available at runtime.
+       ("python-matplotlib" ,python-matplotlib)))
+    (home-page "https://github.com/JuliaPy/PyPlot.jl")
+    (synopsis "Plotting for Julia based on matplotlib.pyplot")
+    (description "This module provides a Julia interface to the Matplotlib
+plotting library from Python, and specifically to the @code{matplotlib.pyplot}
+module.  PyPlot uses the Julia PyCall package to call Matplotlib directly from
+Julia with little or no overhead (arrays are passed without making a copy).")
+    (license license:expat)))
+
 (define-public julia-quadgk
   (package
     (name "julia-quadgk")